Here, we will discuss how to write EC for heteronuclear diatomic molecule. We will also how to calculate bond order of NO, CO molecules and NO+, NO-, CO+ ions
What is bond order of NO heteronuclear diatomic molecule
- Total number of electrons in NO = 7 ( N ) + 8 ( O ) = 15 e-
- EC for NO = KK sigma 2s2, sigma* 2s2, sigma 2pz2, pi2px2, pi2py2, pi*2px1
- Bond order of NO = 1/2 ( 8 – 3 ) = 2.5
- EC for NO+ = KK sigma 2s2, sigma* 2s2, sigma 2pz2, pi2px2, pi2py2
- Bond order of NO+ = 1/2 ( 8 -2 ) = 3
- EC for NO- = KK sigma 2s2, sigma* 2s2, sigma 2pz2, pi2px2, pi2py2, pi*2px2
- Bond order of NO– = 1/2 ( 8 -4 ) = 2
What is bond order of CO diatomic molecule
- Total number of electrons in CO = 6 ( C ) + 8 ( O ) = 14 e-
- EC for CO = KK sigma 2s2, sigma* 2s2, sigma 2pz2, pi2px2, pi2py2
- Bond order of CO = 1/2 ( 8 – 2 ) = 3
- EC for CO+ = KK sigma 2s2, sigma* 2s2, sigma 2pz2, pi2px2, pi2py1
- Bond order of CO+ = 1/2 ( 7 – 2 ) = 2.5
- But the actual bond order of CO+ = 3.5
What is bond order of CN- ion
- Total number of electrons in CN– = 6 ( C ) + 7 ( N ) + 1= 14 e-
- EC for CN– = KK sigma 2s2, sigma* 2s2, pi2px2, pi2py2, sigma 2pz2
- Bond order of CN– = 1/2 ( 8 – 2 ) = 3
What is bond order of BN heteronuclear diatomic molecule
- Total number of electrons in BN = 5 ( B ) + 7 ( N ) + 1= 12 e-
- EC for BN = KK sigma 2s2, sigma* 2s2, pi2px2, pi2py2
- Bond order of BN = 1/2 ( 6 – 2 ) = 2
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